Award of 12th TT Spisska Borovicka C 8.9.2000

This is the award by Peter Gvozdják of TT that was announced on CCM too.
There were 10 existing CYCLONE problems with castling until this tourney. And, there came another 9 new positions to Spisska borovicka! I have chosen one of the most difficult combinations, and that is why I have published the announcement earlier on the web site of Juraj Lörinc.

Yes, and people gave me a good proof it was the right decision. So this year, for the first time, I knew also the authors of problems. But not so much changed concerning the winners...

I received 9 examples. Of them, several did use the castling just as another move - I would say as a technical move. The others, and for this reason being better problems, did use it in a natural way - using the castling paradox, or so.

Commended ex aequo:
1lor (Lörinc)
5sab (Sabol)
7kle (Klemanic)
These are the cases I have been talking about: There is no trick, just the castling is distinguished from single K or R moves.

Juraj Lörinc
Commended ex aequo 12th TT Spisska Borovicka C 8.9.2000

1.VAe6? thr. 2.0-0#, 1...Md5 2.Md6#, 1...g4!,

1.Md6! thr. 2.VAe6#, 1...Mxd5 2.0-0#.

#2 (9+6)
1+0 vao, 2+2 moose

Frantisek Sabol
Commended ex aequo 12th TT Spisska Borovicka C 8.9.2000

a) 1.0-0! thr. 2.Be2#, 1...Qxd6 2.Qxc3#,

b) 1.Be2! thr. 2.Qxc3#, 1...Qxd6 2.0-0#.

#2 (13+6)
b) Circe

Emil Klemanic
Commended ex aequo 12th TT Spisska Borovicka C 8.9.2000

1.Bg3? thr. 2.0-0-0#, 1...BHf4 2.RLg4#, 1...RLd5!,

1.RLg4! thr. 2.Bg3#, 1...BHxf4 2.0-0-0#.

#2 (11+7)
rook lion d4, d8, bishopper a7, d7

3rd HM 8uit (Versmissen, Uitenbroek) is quite an interesting combination of Equihoppers with Beamtenschach.

Koen Versmissen
Hans Uitenbroek

3rd HM 12th TT Spisska Borovicka C 8.9.2000

1.0-0? thr. 2.Gd4#, 1...e3 2.Sd3#, 1...bxa4!,

1.Gd4! thr. 2.Sd3#, 1...e3 2.0-0#.

#2 (6+10)
2+0 grasshopper, 0+4 equihopper

2nd HM 6man (Manolescu) Shedey cycle with nice play along chinese lines.

Mircea Manolescu
2nd HM 12th TT Spisska Borovicka C 8.9.2000

1.LEe5? thr. 2.Se7#, 1...Kf8, 0-0 2.Sd6, Sf6#, 1...Bg8!,

1.Bd4! thr. 2.Sd6#, 1...Kf8, 0-0 2.Sf6, Se7#.

+++ Composition In the Spotlight (CIS) No. 5 +++

Spotlight comment by Juraj Lörinc:

It was very sad piece of news... Mircea Manolescu is no longer among us... he died this year... That's why I decided to light this fairy twomover proving that although almost everyone had known him as an excellent orthodox composer, especially in the field of #3, he was able to use the fairy pieces as well and on a high level!

This #2 was composed in the limited time during the world congress of chess composition at Pula, Croatia. In this way you have to look at the construction that probably could be improved, but the mechanism is very good.

The try 1.LEe5 removes leo from f-file to e-file, close Bc3-g7-h8, but prepares LEe5-h8 and threats double antibattery mate Se7# with pin of Be8. 1...Kf8 defends by run to potential flight g7 (theme F motive), but allows other antibattery mate Sd6# (it didn't threat because of PAd1). The castling 1...0-0 has the same defence motive, the other flight is h8, so White choses doublecheck mate Sf6# with indirect antibattery guarding of g7 and h8.

The key 1.Bd4 closes PAd1-d6 and opens PAc1-c5 in anticipation, thus threats direct mate Sd6# with indirect antibattery guard of f8. 1...Kf8 defends by turning indirect battery into potentially guarded direct antibattery (cool motive!), but allows mate Sf6# despite guard on f6, finally defence 1...0-0 changes 1.Sd6 into check by guarded battery, but White choses to mate by doublecheck mate Se7# not closing d4-h8 line.

Very-very complicated fairy motivation by so-known orthodox master!

#2 (10+11)
1+0 leo, 2+1 vao, 0+3 pao

1st HM 2lor (Lörinc) Lacny cycle with both (!) white castlings plus additional changes in non-thematic phase. Very good idea, but not so complicated to build. The stipulation runs "reflex check in two".

Juraj Lörinc
on occasion zacikmo-28
1st HM 12th TT Spisska Borovicka C 8.9.2000

1.Ke2? zz, 1...d6, f6, c6 2.f3, d3, !,

1.d3? zz, 1...d6, f6, c6 2.0-0, Ke2, 0-0-0 BHc5+, BHc4+, RHe5+, 1...c5!,

1.f3! zz, 1...d6, f6, c6 2.Ke2, 0-0-0, 0-0 BHg4+, BHg5+, RHe5+,

r+2 (11+7)
2+1 nightrider-hopper, 2+3 bishopper

3rd Prize 4asc (Lörinc, Caillaud, Aschwanden) Beautiful reflexmate with 4-fold Lacny cycle and both white castlings, and more, also the other white moves with the same rooks on same squares!

Juraj Lörinc
Michel Caillaud
Reto Aschwanden

3rd Prize 12th TT Spisska Borovicka C 8.9.2000

1.Re4? t, 1...Rc7, Rd7, Re7, Rxf8 2.0-0, Rd1, Rf1, 0-0-0 Qh2, Qf2, Qd2, Qb2#, 1...h4!,

1.h4! t, 1...Rc7, Rd7, Re7, Rxf8 2.Rd1, Rf1, 0-0-0, 0-0 Qf2, Qd2, Qb2, Qh2#.

r#2 (10+12)
2+0 vao, 0+4 nonstop equihopper
paralysing unit d8, e3, f8, g8

2nd Prize 9asc (Caillaud, Aschwanden, Maeder) The Djurasevic cycle 4/1! The most difficult construction in this tourney. Reto told me they worked on it until 4 AM in the last night. Only then computer said: You can go to bed, it is correct!

Michel Caillaud
Reto Aschwanden
Thomas Maeder

2nd Prize 12th TT Spisska Borovicka C 8.9.2000

1.Sc2? thr. 2.RLee6(xe5) RLe3(xf3)#, 1...Sd4, Bd4 2.RLce6(xd6), 0-0-0 Sc2, Bxb2#, 1...Re6!,

1.0-0-0! thr. 2.Sc2 Rxd1#, 1...Sxd4, Bxd4 2.RLee6(xe5), RLce6(xd6) Sab3, Bxb2#.

r#2 (10+16)
1+1 bishop locust, 4+2 rook locust

1st Prize 3cai (Caillaud) "Only" 3-fold Djurasevic cycle, but I have decided to put this first. It shows the whole theme with very logically included white castling without any fairy elements. I think this reflexmate is the most beautiful problem of the tourney, and, of course, very difficult, too.

Michel Caillaud
1st Prize 12th TT Spisska Borovicka C 8.9.2000

1.0-0-0? thr. 2.Bc3 Rxd1#, 1...Sxd4 2.Re4 Sxb3#, 1...Sd6!,

1.Bc3! thr. 2.Re4 Bh4#, 1...Sd4 2.0-0-0 Sxb3#.

+++ Composition In the Spotlight (CIS) No. 10 +++

Spotlight comment by Juraj Lörinc:

Already second spotlight flash on this award, following #2 with Chinese pieces by Mircea Manolescu. I am very often amazed by creativity of some authors of reflex mates. Here we see fine interplay of castling, constrained pair of white pieces (bishop, rook) and black knight. Only few solvers would expect that mate Sxb3 will be the featured in variations in both try and solution. 1.0-0-0 prepares rook mate on first rank, but bS closes the line in defence. If it plays to d4, rook hides away and Sxb3# follows. If it plays to d6, no mate... In the solution, the other mate is threatened, using opened d-line. That is why knight has to play to d4 and now 3rd rank is already closed, d-file as well and thus after castling follows the known checkmate. Note the role of bQ backing up both rooks and bishop.

r#2 (12+10)

Peter Gvozdják, beach of Pula, 8-th September 2000.

Comments to Juraj Lörinc.
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