Originals from Pat a Mat 31 - third part

This is the 3rd of 3 files containing Pat a Mat 31 originals. The others are:
First part
Second part

The solutions of originals should be sent to the following adress (preferably before 31.3.2001):
Marian Cervenka
Starhradska 6
SK-85105 BRATISLAVA
Slovakia
They will appear here after their publication in printed version of Pat a Mat.

Comments to fairy originals, originally in Slovak, are by Juraj Lörinc. Translated to English by Juraj Lörinc.
Harri Hurme
Espoo, FIN
989 Pat a Mat 31 - December 2000

Comment on original for solving:
Few pieces - lesser problems? Fairies are simpler today, considering number of pieces on the board, but used fairy elements may prepare hard time to our solvers.

Not 989 - they have already some lion feeling, I think. Three phase formal theme with almost all moves included looks like simple mechanism.









#2 (6+4)
3+1 lion
Christian Poisson
Jacques Rotenberg
Nantes & Paris, F
990 Pat a Mat 31 - December 2000

Comment on original for solving:
Circe Assassin of 990 may be well explained with the help of set play. 1...Vexe8(Sf1) removes Vf1 from the board. Also Re6 leaves pc6, White can mate by 2.Qc2# as Black has no longer defence 2.Vxc6(pc2) with removal of queen, of course, 2...Kxc2(Dd1)?? isn't enough. The main content is shown in try and solution with "cyclone" theme.









#2 (7+7)
Circe Assassin
Olivier Ronat
Lille, F
991 Pat a Mat 31 - December 2000

Comment on original for solving:
Elephants of 991 are very agile pieces, white one needs to tame black one (stalemate him), for that sake he promotes second (non-royal) elephant from his own pawn left on 7nd rank thanks to Sentinelles condition in 2nd move.









h=3 (1+1)
Sentinelles
1+1 royal elephant
b) b3 -» b2
c) g4 -» g7
Juraj Lörinc
Dubnica nad Vahom, SVK
992 Pat a Mat 31 - December 2000

Comment on original for solving:
Only one mating position exists in fact with material and condition of 992 - in orthogonal (e. g. wKCc1, wKCc2, bKc6, holes b5, b6, b7, c7, d7, d6, d5) and diagonal version - it only remains to place them well on the board.









h#5 (2+1)
Haaner chess
2+0 contragrasshopper
b) e3 -» f4
Valerij Nebotov
Anatolij Chandurin
Charkov, UKR
993 Pat a Mat 31 - December 2000

Comment on original for solving:
Finally, one of 993 solutions, weaker one, is: 1.Sxb7=bp(pc6) 2.b5 ... 5.b2 6.bxc1=bS 7.Sh6 8.Sg7=bp Jd8=wD#. The other solution has the same first move.









ser-#8 (5+2)
Circe Equipollent, Wandelschach without change of colour
nightrider c1
2 solutions

Comments to Juraj Lörinc.
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