As you might know, Marianka Cup composing tourney allowing 30 days for composers was this year announced for any kind of problems featuring hoppers changing direction over the hurdle: moose, eagle, sparrow or hamster. The tourney was very successful with very good problems produced. But the choice of Marianka Cup has provided me an idea for fairy solving tourney too: to let solver try the turning hoppers as well. I added grasshopper as the best known fairy piece and voila!

There were 11 problems to be solved within time limit 100 minutes and each of them could bring 30 points to the solver.

The results were as follows:

1. Michel Caillaud - 293 points (of 330 possible)

2. Marek Kolcak - 115 points

3. Milan Svrcek - 30 points

4. Ladislav Packa - 0 points

Of the 11 problems solved during the competition, 4 were already present on the CCM:

- #2 with grasshoppers - the easiest twomover solved for 30 by everyone except Laco

- h#3 with grasshoppers - helpmate with 2 solutions with mates over immobilized hurdle - solved securely by winner

- s#2 with grasshoppers - well solved by Michel, who even has fallen for a while for one try, but then corrected himself

- ser-h#8 with grasshopper - Marek and Michel found both solutions for full points

The other problems from the competition are given below.

Stephen Emmerson5th HM R. McWilliam MT 1999-2001 |
1.Bxe7! th. 2.Bg5# |

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#2 (10+5) 5+2 moose |

Juraj LörincPrize New Year Tourney Thema Danicum 2003 |
1.Hec6? th. 2.He2# |

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#2 (11+7) 1+1 grasshopper, 2+2 hamster |

Chris FeatherStrateGems 2010 |
1.Qe2 d8EA 2.EAe4 Qc3# |

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h#2 (4+10) 0+5 eagle 3.1.1.1 |

Yoshikazu UedaProblem Paradise 2008 |
1.Sf6 Mxf8 2.Rxf8 Mxg7# |

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h#2 (3+16) 2+0 moose 5.1.1.1 |

Juraj Lörinc5th Commendation Crete 2010 |
1.Rg5 Mh5 2.Rxb5 Kxb5 3.Kh3 Qa8 4.Rg4 Qh1# |

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h#4 (8+5) moose c1 3.1.1... |

Harald Grubert5th Prize 65th TT feenschach 2013 |
a) 1.Ke2 2.Mf1 5.Kb5 6.Mca5 7.Ka6 8.Ma7 SPb6# |

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ser-h#8 (2+3) 1+0 sparrow, 0+2 moose b) c5 -» f6 |

Václav KotesovecPhénix 2011 |
1...EAb8 2.Ka5 EAc7 3.Ka6 Kb4= |

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h=2,5 (2+3) eagle d4 2.1.1.1.1 |

Comments to
Juraj Lörinc.

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