Originals from Pat a Mat 25 - third part

Comment on original for solving:
Fairies are, on the contrary to selfmates and helpmates, all from abroad. They are much lighter than PaM 23 originals. Republican chess (used in 409) is one very original fairy condition and incidentally magazine Quartz dedicated its 3rd TT to it.

Solution:
1.a6! t.
1...Sb7, Sc6 2.Jxb7(Ka5)#, Jxc6(Ka5)#

1.b6! t.
1...Sb7, Sc6 2.Jc6(Ka6)#, Jb7(Kb5)#

Reciprocal change in this problem easily illustrates huge possibilities of Republican chess. (JL) While the first solution I have seen easily from diagram, second was difficult. Reciprocal change is very unusual here. (Bohus Moravcik).

Comment on original for solving:
Many Slovak chess composition zealots met transmuting kings during preparation for 6th WCCT. 410 has nice analogy.

Solution:
Unfortunately bph5 was by my mistake placed on h5. I apologize author and solvers. (JL)

1.De2+ Kd6 2.Sd3 Je6# (this solution didn't exist in diagram position)
1.Dg6+ Kc4 2.Ve6 Jd3#

Nice D-O analogy also in disallowing of capture of checkmating knight by queen. (JL) Due to error we decided not to count this problem in solving competition. Anyway we took one comment that well lights the ideas behind this fairy genre:
I started from the fact that black king has changed movement only in the moment of check, but after its defending he is again normal. That's why 1.Da4+ Kd6 2. Ve4 Jd3+ isn't solution because of d3, d5, e6, g6 flights. If the mutation remained after check, then this would have been solution. (This is exactly the point of Karol Mlynka's invention, super-transmuting king. (JL)) Transmuting king can be mated only by covered piece, otherwise he can capture it. (Bohus Moravcik).

Comment on original for solving:
Similar analogy is contained in 411, Michal writes (with small question mark): "Probably letztform ?".

Solution:
1.Jf6 SLg8 2.Jd6 Kb4 3.Jf5 Jf7#
1.Jd6 VLh4 2.Je3 Kb3 3.Jef5 Jg4#

Total analogy of two solution and model mates. Black pb5 defends some cooks, author regretted its presence too... (JL) Normally is the use of fairy pieces deemed by motivation elements, here they (SL instead of S, VL instead of V) allow easy move ordering, they are definitely improving. (Bohus Moravcik).

Comment on original for solving:
Originals 412 and 414 use the same element in different situations, the element highly Madrasi specific.

Solution:
There are 10 black pieces that must be immobilized, that seems to me too much also for Madrasi, so I gave up immediately. (Bohus Moravcik) Oh yes, in both positions there the same trick that allows not to take care about individual pieces. (JL)

a) 1.Vc6 Ve3 2.Vc3+ Jf4+ 3.Ke5 d4=

b) 1.Ve6 De3 2.Dc3+ Jb4+ 3.Kc5 d4=

Model stalemates with use of Madrasi specialities after analogical (a bit symmetrical) play. If you like to know more about Madrasi, consult article "Madrasi trochu inak" in this issue, Ivan Skoba prepares longer article about Madrasi too.(JL)

Comment on original for solving:
413 works out theme done by Václav already many times, this time with soft Circe touch.

Solution:
1...Jd3+ 2.Kc4 Cd4 3.d5 Je5+ 4.Kc5 Ka5=
1...Cg5 2.Kc5 Cb5 3.d6 Cd5 4.Kc6 Je6=
1...Jd5+ 2.Kc5 Cd6 3.Kc6 Je7+ 4.Kc7 Ka7=

Triple echo of ideal Circe-stalemate. Soft work by one of genre masters. (JL) First solutions took ages, others followed immediately. (Bohus Moravcik)

Comment on original for solving:
Originals 412 and 414 use the same element in different situations, the element highly Madrasi specific.

Solution:
1.Kb6 2.a5 3.Kb7 7.a1J 9.Jxc5 14.d1S 16.Sc8 17.Jd7 18.c5 19.Kc7 23.c1D 25.Db7 26.Jb6 Sh2#.

Twice black cannot immediately continue in his pawn march due to temporary paralysis, that's why he must do necessary moves by king. Interesting idea with 3 promotions in attractive position.

Unfortunately, there is a cook:
1.Kb6 2.a5 3.Kb7 7.a1J 9.Jxc5 10.Jd7! 11.c5 12.Kc7 16.c1D 18.Db7 23.d1S 24. Jb6 26.Sc8 Sh2# (found by Olivier Ronat). Bohus Moravcik sent in wrong solution, he thought he can mate in 25th move as he didn't think about pawn stopping after 2.a5. (JL)