Originals from Pat a Mat 23 - second part

Comment on original for solving:
202 has 2 tries and logically following Nowotny.

Solution:
1.Jc4? Sxe5+!, 1.Sc4? Vxg1+!, 1.Vg5! hr. 2.Jc4 a 2.Sc4, 1...Vxg5, Sxg5 2.Jc4, Sc4

Nowotny without bigger innovation.

Comment on original for solving:
White uses black interference in 203 by the same Polish author.

Solution:
1.De2! hr. 2.Dxe3, 1...Sf2, Jc4, Vf3, Vf4 2.Jxf5, Jxe6, D:x3, Dxe3+

There is no need to comment further.

Comment on original for solving:
Latvian author in his logic threemover 204 uses interference and anticipatory interference too.

Solution:
1.Sd4 hr. 2.Jc5+ Ka5 3.Sc3#, 1...Vf4 2.fxe8J Vxd4 3.Jc7#, 1...Vc2 2.Ka8 a 3.b8J#, 1...d6 2.f:e8D

There are more promotions than pure mates and interferences here, thus it doesn't make compact whole...

Comment on original for solving:
The only moremover 205 is romantic and it shouldn't make any trouble to solvers.

Solution:
1.Jxd6! hr. 2.Jf7#, 1...Vxd6 2.Sc7 hr. 3.Sxd6#, 2...Sxc5 3.Sxd6+ Sxd6 4.Vxe3+ Jxe3 5.d4+ Jxd4 6.Ve4+ fxe4 7.f4#

Comment on original for solving:
206 is the only helpmate featuring promotions.

Solution:
1...f8D/S#, 1.bxa1J f8D+ 2.Ka4 Da3#, 1.bxa1V f8V 2.Va5 Vf4#

Comment on original for solving:
Twomove helpmates 207-209 are strategical.

Solution:
a) 1.Kf5 Jd3 2.Je6 Jg3#, b) 1.Kd3 Jf4+ 2.Kc4 Jd2#

Mostly unpins of white knights, there is little of other strategy here.

Comment on original for solving:
Twomove helpmates 207-209 are strategical.

Solution:
1.Jxb6 Sb3 2.Kc5 Sa3#, 1.Jxb2 Sd5 2.Ka3 Dc5#

Symmetry of arrival squares with respect to b4, it is quite unusual and nice analogy.

Comment on original for solving:
Twomove helpmates 207-209 are strategical.

Solution:
a) 1.Vf2 Vc2 2.Jxb5 Vd2#, b) 1.Vh5 Sh7 2.Jc5 Sg8#

Selfpins of black knights by capture are overworked in h#2 today.

Comment on original for solving:
210 has 3 surprises (for every position one).

Solution:
a) 1.Se1! Se5 2.Sa5 Jd4 3.Sb6 Jd3#, b) 1.Sc1! Sh8 2.Se3 Jg7 3.Kd4 Jge6#, c) 1.Sb2! Sa5 2.Se5 Jd4 3.Sd6 Jfe6#

Three mid-board model mates after three pure tempo moves by black bishop.

Comment on original for solving:
The sacrifices are main idea in 211.

Solution:
1.Dg4 Sxg4 2.Vdd1 Sxd1 3.b2 Sxa4#, 1.Df5 Sxf5 2.Vd3 Sxd3 3.Sb5 Sxb5#, 1.De6 Sxe6 2.Vd5 Sxd5 3.Sc6 Sxc6#, 1.Db7+ Kxb7 2.Sc6+ Kxc6 3.Vd7 Sxd7#

All white moves are captures, 4 analogical model mates, three of them differs only by location of white bishop.

Comment on original for solving:
Lastly 212 by already deceased author is successful variation on known themes.

Solution:
a) 1.Sxh1! Sg2 2.Jf7 Sb7 3.Sd5 Sc8#, b) 1.Vxf1! Vf2 2.Sd5 Vf7 3.Vf6 Ve7#

Zig-zag movement of black pieces, in D-O analogy, it's a pity that black bishop doesn't start at d5.