Juraj Lörinc 8542 Sachove Umenie 11/1994 Notes: 666 Sent: 54 |
a) 1.Rd4 Bd5 2.Be4 Rh2# |
| |
h#2 (3+9) b) h7 -» a4 |
Juraj Lörinc 3548 Sachova skladba 45/1994 Notes: 683 Sent: 55 |
1.Sg8! zz |
| |
#3 (8+7) Circe 2 solutions |
Juraj Lörinc 3555 Sachova skladba 45/1994 3rd Prize Sachova skladba 1994 Notes: 656 Sent: 56 |
1.Sexg2! th. 2.Sgxf4# |
| |
#2 (9+9) Patrol chess 2 solutions |
Juraj Lörinc 3552 Sachova skladba 45/1994 Comm Sachova skladba 1994 Notes: 686 Sent: 57 |
1.Ba5! zz |
| |
semi-r#4 (12+6) 4+1 grasshopper |
Juraj Lörinc 202 Harmonie 44/1994 Comm Harmonie 1994 Notes: 690 Sent: 58 |
1.Gd8? zz |
| |
#2 (16+8) Patrol chess 7+1 grasshopper |
Hans Peter Rehm Juraj Lörinc 2nd Prize 7. TT Harmonie C 31.8.1994 Notes: 692 Sent: 59 |
1.Se6+? A Kd6! x (2.g3+ Kxd7) |
| |
#2 (14+9) 1+1 Lion, 3+1 Rook lion, 1+2 Bishop lions |
Juraj Lörinc correction of 1798 Phénix 25-26/1994 2nd HM Phénix Directs 1994 Notes: 680 Sent: 60 |
Black king is catched on 2 squares and all white must do is to
capture bSh6 with king. But it turns out that (1.Kh5? Kh7!) white must
loose tempo somewhere... It is possible only in triangle a6-a7-b7, so he must
go with his king for a long journey: 1.Kh3 Kh7 2.Kh2 Kh8 ... 14.Ka7 (Kb7) Kh8
15.Kb7 (Ka7) Kh7 16.Ka6 ... 30.Kh5! d4! (and again until black makes all
available pawn moves) 339.Kh4 Kh7 340.Kh5 Kh8 341.Kxh6#. |
| |
#341 (9+14) Madrasi |
Juraj Lörinc 2000 Phénix 28/1994 NOT CORRECT Notes: 697 Sent: 61 |
Intention: White can mate only by knight or by wazir when Qa1 is removed as Rh2
quards h6 forever. In the course of solution it turns out that the knight will
be the mating unit. White must step-by-step remove black guarding pieces and he must
avoid selfparalyzing: 1.Wc6 ... 19.Wxb1(Bc8) ... 39.Wxb7(Ra8) 40.Wxa7(Bf8) ... 62.Wxa1(Qd8)
63.Wxa2 ... 85.Wxa6 ... 87.Sf6# |
| |
ser-#87 (3+14) Madrasi Rex Inclusiv, Circe 1+6 wazirs |
Comments to
Juraj Lörinc.
Back to main page of Chess Composition Microweb.